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3124104402073 is a prime number
BaseRepresentation
bin101101011101100011001…
…000100001010010011001
3102001122212012121010010011
4231131203020201102121
5402141131211331243
610351105503321521
7441465135161224
oct55354310412231
912048765533104
103124104402073
11aa4a1a542926
124255802b02a1
131987a9161045
14ab2c93ac5bb
15563e9be389d
hex2d763221499

3124104402073 has 2 divisors, whose sum is σ = 3124104402074. Its totient is φ = 3124104402072.

The previous prime is 3124104402061. The next prime is 3124104402149. The reversal of 3124104402073 is 3702044014213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2937206413584 + 186897988489 = 1713828^2 + 432317^2 .

It is an emirp because it is prime and its reverse (3702044014213) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3124104402073 is a prime.

It is not a weakly prime, because it can be changed into another prime (3124104102073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562052201036 + 1562052201037.

It is an arithmetic number, because the mean of its divisors is an integer number (1562052201037).

Almost surely, 23124104402073 is an apocalyptic number.

It is an amenable number.

3124104402073 is a deficient number, since it is larger than the sum of its proper divisors (1).

3124104402073 is an equidigital number, since it uses as much as digits as its factorization.

3124104402073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 3124104402073 its reverse (3702044014213), we get a palindrome (6826148416286).

The spelling of 3124104402073 in words is "three trillion, one hundred twenty-four billion, one hundred four million, four hundred two thousand, seventy-three".