Base | Representation |
---|---|
bin | 100011100001000101111001… |
… | …0110001000001101100011001 |
3 | 1111222011020102220110010001101 |
4 | 1013002023302301001230121 |
5 | 311422022023423132323 |
6 | 3024235452344151401 |
7 | 122542656554666341 |
oct | 10702136261015431 |
9 | 1458136386403041 |
10 | 312411404114713 |
11 | 905a8a2908a912 |
12 | 2b05750b168561 |
13 | 10542365cac7b7 |
14 | 5720b14dddd21 |
15 | 261b80e43edad |
hex | 11c22f2c41b19 |
312411404114713 has 2 divisors, whose sum is σ = 312411404114714. Its totient is φ = 312411404114712.
The previous prime is 312411404114659. The next prime is 312411404114743. The reversal of 312411404114713 is 317411404114213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 297144231088384 + 15267173026329 = 17237872^2 + 3907323^2 .
It is a cyclic number.
It is not a de Polignac number, because 312411404114713 - 213 = 312411404106521 is a prime.
It is not a weakly prime, because it can be changed into another prime (312411404114743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156205702057356 + 156205702057357.
It is an arithmetic number, because the mean of its divisors is an integer number (156205702057357).
Almost surely, 2312411404114713 is an apocalyptic number.
It is an amenable number.
312411404114713 is a deficient number, since it is larger than the sum of its proper divisors (1).
312411404114713 is an equidigital number, since it uses as much as digits as its factorization.
312411404114713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 37.
Adding to 312411404114713 its reverse (317411404114213), we get a palindrome (629822808228926).
The spelling of 312411404114713 in words is "three hundred twelve trillion, four hundred eleven billion, four hundred four million, one hundred fourteen thousand, seven hundred thirteen".
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