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312411404114713 is a prime number
BaseRepresentation
bin100011100001000101111001…
…0110001000001101100011001
31111222011020102220110010001101
41013002023302301001230121
5311422022023423132323
63024235452344151401
7122542656554666341
oct10702136261015431
91458136386403041
10312411404114713
11905a8a2908a912
122b05750b168561
1310542365cac7b7
145720b14dddd21
15261b80e43edad
hex11c22f2c41b19

312411404114713 has 2 divisors, whose sum is σ = 312411404114714. Its totient is φ = 312411404114712.

The previous prime is 312411404114659. The next prime is 312411404114743. The reversal of 312411404114713 is 317411404114213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 297144231088384 + 15267173026329 = 17237872^2 + 3907323^2 .

It is a cyclic number.

It is not a de Polignac number, because 312411404114713 - 213 = 312411404106521 is a prime.

It is not a weakly prime, because it can be changed into another prime (312411404114743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156205702057356 + 156205702057357.

It is an arithmetic number, because the mean of its divisors is an integer number (156205702057357).

Almost surely, 2312411404114713 is an apocalyptic number.

It is an amenable number.

312411404114713 is a deficient number, since it is larger than the sum of its proper divisors (1).

312411404114713 is an equidigital number, since it uses as much as digits as its factorization.

312411404114713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 37.

Adding to 312411404114713 its reverse (317411404114213), we get a palindrome (629822808228926).

The spelling of 312411404114713 in words is "three hundred twelve trillion, four hundred eleven billion, four hundred four million, one hundred fourteen thousand, seven hundred thirteen".