Base | Representation |
---|---|
bin | 100011100001000111001010… |
… | …1011110110111100110101011 |
3 | 1111222011111111011021201220111 |
4 | 1013002032111132313212223 |
5 | 311422043121303303003 |
6 | 3024241023304035151 |
7 | 122543114323663201 |
oct | 10702162536674653 |
9 | 1458144434251814 |
10 | 312414134041003 |
11 | 905aa0aa056945 |
12 | 2b057b51462ab7 |
13 | 105426ac7437b7 |
14 | 5720cd37c3071 |
15 | 261b91de36e6d |
hex | 11c23957b79ab |
312414134041003 has 2 divisors, whose sum is σ = 312414134041004. Its totient is φ = 312414134041002.
The previous prime is 312414134040973. The next prime is 312414134041013. The reversal of 312414134041003 is 300140431414213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312414134041003 - 225 = 312414100486571 is a prime.
It is a super-2 number, since 2×3124141340410032 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312414134041013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156207067020501 + 156207067020502.
It is an arithmetic number, because the mean of its divisors is an integer number (156207067020502).
Almost surely, 2312414134041003 is an apocalyptic number.
312414134041003 is a deficient number, since it is larger than the sum of its proper divisors (1).
312414134041003 is an equidigital number, since it uses as much as digits as its factorization.
312414134041003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 312414134041003 its reverse (300140431414213), we get a palindrome (612554565455216).
The spelling of 312414134041003 in words is "three hundred twelve trillion, four hundred fourteen billion, one hundred thirty-four million, forty-one thousand, three".
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