Base | Representation |
---|---|
bin | 1110001101010011001110… |
… | …01111000001010111111111 |
3 | 11002121211110222100021212020 |
4 | 13012221213033001113333 |
5 | 13043342311432232033 |
6 | 150240552425411223 |
7 | 6403153461031026 |
oct | 706514717012777 |
9 | 132554428307766 |
10 | 31243324102143 |
11 | 9a56245a4233a |
12 | 36071ba039b13 |
13 | 145830467a14a |
14 | 7a02837338bd |
15 | 392a9d2106b3 |
hex | 1c6a673c15ff |
31243324102143 has 32 divisors (see below), whose sum is σ = 42335962690560. Its totient is φ = 20491712916480.
The previous prime is 31243324102141. The next prime is 31243324102147. The reversal of 31243324102143 is 34120142334213.
It is not a de Polignac number, because 31243324102143 - 21 = 31243324102141 is a prime.
It is a super-2 number, since 2×312433241021432 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31243324102141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 233998963 + ... + 234132443.
It is an arithmetic number, because the mean of its divisors is an integer number (1322998834080).
Almost surely, 231243324102143 is an apocalyptic number.
31243324102143 is a deficient number, since it is larger than the sum of its proper divisors (11092638588417).
31243324102143 is a wasteful number, since it uses less digits than its factorization.
31243324102143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137087.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 31243324102143 its reverse (34120142334213), we get a palindrome (65363466436356).
The spelling of 31243324102143 in words is "thirty-one trillion, two hundred forty-three billion, three hundred twenty-four million, one hundred two thousand, one hundred forty-three".
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