Base | Representation |
---|---|
bin | 101101011101110000110… |
… | …010011110001011101101 |
3 | 102001200110011200122210120 |
4 | 231131300302132023231 |
5 | 402142113334100323 |
6 | 10351144325555153 |
7 | 441503616411456 |
oct | 55356062361355 |
9 | 12050404618716 |
10 | 3124333503213 |
11 | aa50278a1a0a |
12 | 425624b75ab9 |
13 | 198814767150 |
14 | ab30b9a812d |
15 | 5640ed9a5e3 |
hex | 2d770c9e2ed |
3124333503213 has 32 divisors (see below), whose sum is σ = 4495961500800. Its totient is φ = 1918494823680.
The previous prime is 3124333503211. The next prime is 3124333503217. The reversal of 3124333503213 is 3123053334213.
It is not a de Polignac number, because 3124333503213 - 21 = 3124333503211 is a prime.
It is a super-2 number, since 2×31243335032132 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3124333503211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 88688943 + ... + 88724163.
It is an arithmetic number, because the mean of its divisors is an integer number (140498796900).
Almost surely, 23124333503213 is an apocalyptic number.
It is an amenable number.
3124333503213 is a deficient number, since it is larger than the sum of its proper divisors (1371627997587).
3124333503213 is a wasteful number, since it uses less digits than its factorization.
3124333503213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40109.
The product of its (nonzero) digits is 58320, while the sum is 33.
Adding to 3124333503213 its reverse (3123053334213), we get a palindrome (6247386837426).
The spelling of 3124333503213 in words is "three trillion, one hundred twenty-four billion, three hundred thirty-three million, five hundred three thousand, two hundred thirteen".
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