Base | Representation |
---|---|
bin | 101101011110010110111… |
… | …101011011110000001011 |
3 | 102001202002210201202012101 |
4 | 231132112331123300023 |
5 | 402144421310123201 |
6 | 10351332044054231 |
7 | 441525523654636 |
oct | 55362675336013 |
9 | 12052083652171 |
10 | 3124973911051 |
11 | aa5326339893 |
12 | 425783534377 |
13 | 1988b73400b5 |
14 | ab36ca6cc1d |
15 | 5644b1ead01 |
hex | 2d796f5bc0b |
3124973911051 has 2 divisors, whose sum is σ = 3124973911052. Its totient is φ = 3124973911050.
The previous prime is 3124973911009. The next prime is 3124973911067. The reversal of 3124973911051 is 1501193794213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3124973911051 - 27 = 3124973910923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3124973910992 and 3124973911010.
It is not a weakly prime, because it can be changed into another prime (3121973911051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562486955525 + 1562486955526.
It is an arithmetic number, because the mean of its divisors is an integer number (1562486955526).
Almost surely, 23124973911051 is an apocalyptic number.
3124973911051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124973911051 is an equidigital number, since it uses as much as digits as its factorization.
3124973911051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 46.
The spelling of 3124973911051 in words is "three trillion, one hundred twenty-four billion, nine hundred seventy-three million, nine hundred eleven thousand, fifty-one".
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