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312512491 is a prime number
BaseRepresentation
bin10010101000001…
…000111111101011
3210210001021112201
4102220020333223
51120000344431
651002121031
710513212064
oct2250107753
9723037481
10312512491
11150450295
12887b0177
134c98c145
142d70d56b
151c681461
hex12a08feb

312512491 has 2 divisors, whose sum is σ = 312512492. Its totient is φ = 312512490.

The previous prime is 312512443. The next prime is 312512503. The reversal of 312512491 is 194215213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312512491 - 27 = 312512363 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (312512441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156256245 + 156256246.

It is an arithmetic number, because the mean of its divisors is an integer number (156256246).

Almost surely, 2312512491 is an apocalyptic number.

312512491 is a deficient number, since it is larger than the sum of its proper divisors (1).

312512491 is an equidigital number, since it uses as much as digits as its factorization.

312512491 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2160, while the sum is 28.

The square root of 312512491 is about 17678.0228249655. The cubic root of 312512491 is about 678.6134455724.

The spelling of 312512491 in words is "three hundred twelve million, five hundred twelve thousand, four hundred ninety-one".