Base | Representation |
---|---|
bin | 1001000110000110100… |
… | …10010011110001111101 |
3 | 1002212122122020012100100 |
4 | 10203003102103301331 |
5 | 20110012041031140 |
6 | 355322243351313 |
7 | 31402250121330 |
oct | 4430322236175 |
9 | 1085578205310 |
10 | 312514002045 |
11 | 11059a009253 |
12 | 50698382539 |
13 | 2361560b84b |
14 | 111a911c617 |
15 | 81e1111530 |
hex | 48c3493c7d |
312514002045 has 24 divisors (see below), whose sum is σ = 619075357056. Its totient is φ = 142863543648.
The previous prime is 312514002037. The next prime is 312514002077. The reversal of 312514002045 is 540200415213.
312514002045 is a `hidden beast` number, since 3 + 1 + 2 + 51 + 400 + 204 + 5 = 666.
It is not a de Polignac number, because 312514002045 - 23 = 312514002037 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 496053657 + ... + 496054286.
It is an arithmetic number, because the mean of its divisors is an integer number (25794806544).
Almost surely, 2312514002045 is an apocalyptic number.
312514002045 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
312514002045 is a deficient number, since it is larger than the sum of its proper divisors (306561355011).
312514002045 is a wasteful number, since it uses less digits than its factorization.
312514002045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 992107961 (or 992107958 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 27.
Adding to 312514002045 its reverse (540200415213), we get a palindrome (852714417258).
The spelling of 312514002045 in words is "three hundred twelve billion, five hundred fourteen million, two thousand, forty-five".
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