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312525613241 is a prime number
BaseRepresentation
bin1001000110000111111…
…10100110100010111001
31002212200110002002220122
410203003332212202321
520110023024110431
6355323340303025
731402450611242
oct4430376464271
91085613062818
10312525613241
111105a5619986
12506a0241a75
1323617b4588a
14111aa8a1cc9
1581e2156a7b
hex48c3fa68b9

312525613241 has 2 divisors, whose sum is σ = 312525613242. Its totient is φ = 312525613240.

The previous prime is 312525613229. The next prime is 312525613247. The reversal of 312525613241 is 142316525213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 277555117225 + 34970496016 = 526835^2 + 187004^2 .

It is an emirp because it is prime and its reverse (142316525213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312525613241 - 214 = 312525596857 is a prime.

It is a super-2 number, since 2×3125256132412 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (312525613247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156262806620 + 156262806621.

It is an arithmetic number, because the mean of its divisors is an integer number (156262806621).

Almost surely, 2312525613241 is an apocalyptic number.

It is an amenable number.

312525613241 is a deficient number, since it is larger than the sum of its proper divisors (1).

312525613241 is an equidigital number, since it uses as much as digits as its factorization.

312525613241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 35.

The spelling of 312525613241 in words is "three hundred twelve billion, five hundred twenty-five million, six hundred thirteen thousand, two hundred forty-one".