Base | Representation |
---|---|
bin | 11101000110111100… |
… | …011000011101100111 |
3 | 2222200012210202121221 |
4 | 131012330120131213 |
5 | 1003002240130111 |
6 | 22205223121211 |
7 | 2154346105435 |
oct | 350674303547 |
9 | 88605722557 |
10 | 31255005031 |
11 | 122896a9978 |
12 | 60832a3207 |
13 | 2c413a7b23 |
14 | 1726db5d55 |
15 | c2ddcc371 |
hex | 746f18767 |
31255005031 has 4 divisors (see below), whose sum is σ = 31261300000. Its totient is φ = 31248710064.
The previous prime is 31255005013. The next prime is 31255005043. The reversal of 31255005031 is 13050055213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31255005031 - 25 = 31255004999 is a prime.
It is a super-3 number, since 3×312550050313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31255004987 and 31255005005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31255005931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3140031 + ... + 3149968.
It is an arithmetic number, because the mean of its divisors is an integer number (7815325000).
Almost surely, 231255005031 is an apocalyptic number.
31255005031 is a deficient number, since it is larger than the sum of its proper divisors (6294969).
31255005031 is an equidigital number, since it uses as much as digits as its factorization.
31255005031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6294968.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 31255005031 in words is "thirty-one billion, two hundred fifty-five million, five thousand, thirty-one".
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