Base | Representation |
---|---|
bin | 1011101001001011… |
… | …1000110100011001 |
3 | 22001211012112111011 |
4 | 2322102320310121 |
5 | 22400112412442 |
6 | 1234050333521 |
7 | 140311266151 |
oct | 27222706431 |
9 | 8054175434 |
10 | 3125513497 |
11 | 13642a8607 |
12 | 73288a2a1 |
13 | 3aa6bbb92 |
14 | 219159761 |
15 | 1345d8117 |
hex | ba4b8d19 |
3125513497 has 2 divisors, whose sum is σ = 3125513498. Its totient is φ = 3125513496.
The previous prime is 3125513449. The next prime is 3125513513. The reversal of 3125513497 is 7943155213.
3125513497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2708577936 + 416935561 = 52044^2 + 20419^2 .
It is a cyclic number.
It is not a de Polignac number, because 3125513497 - 211 = 3125511449 is a prime.
It is not a weakly prime, because it can be changed into another prime (3125513407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562756748 + 1562756749.
It is an arithmetic number, because the mean of its divisors is an integer number (1562756749).
Almost surely, 23125513497 is an apocalyptic number.
It is an amenable number.
3125513497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3125513497 is an equidigital number, since it uses as much as digits as its factorization.
3125513497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 113400, while the sum is 40.
The square root of 3125513497 is about 55906.2921056298. The cubic root of 3125513497 is about 1462.0889433520.
The spelling of 3125513497 in words is "three billion, one hundred twenty-five million, five hundred thirteen thousand, four hundred ninety-seven".
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