Base | Representation |
---|---|
bin | 1110001101110110011011… |
… | …10111010010011100101111 |
3 | 11002200122021021020011222222 |
4 | 13012323031313102130233 |
5 | 13044200014301144210 |
6 | 150253400202425555 |
7 | 6404423045604542 |
oct | 706731567223457 |
9 | 132618237204888 |
10 | 31262225803055 |
11 | 9a63265508a65 |
12 | 360a9b42022bb |
13 | 145a02764b360 |
14 | 7a1157c00859 |
15 | 39330782e655 |
hex | 1c6ecddd272f |
31262225803055 has 32 divisors (see below), whose sum is σ = 40993497194496. Its totient is φ = 22747659577344.
The previous prime is 31262225803013. The next prime is 31262225803079. The reversal of 31262225803055 is 55030852226213.
It is not a de Polignac number, because 31262225803055 - 230 = 31261152061231 is a prime.
It is a super-2 number, since 2×312622258030552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31262225802997 and 31262225803015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1712594 + ... + 8090576.
It is an arithmetic number, because the mean of its divisors is an integer number (1281046787328).
Almost surely, 231262225803055 is an apocalyptic number.
31262225803055 is a deficient number, since it is larger than the sum of its proper divisors (9731271391441).
31262225803055 is a wasteful number, since it uses less digits than its factorization.
31262225803055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6379107.
The product of its (nonzero) digits is 864000, while the sum is 44.
The spelling of 31262225803055 in words is "thirty-one trillion, two hundred sixty-two billion, two hundred twenty-five million, eight hundred three thousand, fifty-five".
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