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3130022211233 is a prime number
BaseRepresentation
bin101101100011000011110…
…111001010111010100001
3102002020010121222222011012
4231203003313022322201
5402240241141224413
610353525022430305
7442064603550161
oct55430367127241
912066117888135
103130022211233
11aa7486a364a5
12426752132395
131992101b0478
14ab6cb3045a1
15566444e37a8
hex2d8c3dcaea1

3130022211233 has 2 divisors, whose sum is σ = 3130022211234. Its totient is φ = 3130022211232.

The previous prime is 3130022211187. The next prime is 3130022211343. The reversal of 3130022211233 is 3321122200313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1742460720529 + 1387561490704 = 1320023^2 + 1177948^2 .

It is an emirp because it is prime and its reverse (3321122200313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3130022211233 - 216 = 3130022145697 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3130022211199 and 3130022211208.

It is not a weakly prime, because it can be changed into another prime (3130822211233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565011105616 + 1565011105617.

It is an arithmetic number, because the mean of its divisors is an integer number (1565011105617).

Almost surely, 23130022211233 is an apocalyptic number.

It is an amenable number.

3130022211233 is a deficient number, since it is larger than the sum of its proper divisors (1).

3130022211233 is an equidigital number, since it uses as much as digits as its factorization.

3130022211233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 3130022211233 its reverse (3321122200313), we get a palindrome (6451144411546).

The spelling of 3130022211233 in words is "three trillion, one hundred thirty billion, twenty-two million, two hundred eleven thousand, two hundred thirty-three".