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31301300153 is a prime number
BaseRepresentation
bin11101001001101100…
…111110111110111001
32222210102220210121002
4131021230332332321
51003101113101103
622213555254345
72155450442564
oct351154767671
988712823532
1031301300153
111230284a102
1260968aa3b5
132c4ab66aa6
14172d1c74db
15c32ec4488
hex749b3efb9

31301300153 has 2 divisors, whose sum is σ = 31301300154. Its totient is φ = 31301300152.

The previous prime is 31301300143. The next prime is 31301300171. The reversal of 31301300153 is 35100310313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26468686864 + 4832613289 = 162692^2 + 69517^2 .

It is an emirp because it is prime and its reverse (35100310313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31301300153 - 212 = 31301296057 is a prime.

It is not a weakly prime, because it can be changed into another prime (31301300143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15650650076 + 15650650077.

It is an arithmetic number, because the mean of its divisors is an integer number (15650650077).

Almost surely, 231301300153 is an apocalyptic number.

It is an amenable number.

31301300153 is a deficient number, since it is larger than the sum of its proper divisors (1).

31301300153 is an equidigital number, since it uses as much as digits as its factorization.

31301300153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405, while the sum is 20.

Adding to 31301300153 its reverse (35100310313), we get a palindrome (66401610466).

The spelling of 31301300153 in words is "thirty-one billion, three hundred one million, three hundred thousand, one hundred fifty-three".