Base | Representation |
---|---|
bin | 1110001110111111100111… |
… | …11111001101110100011001 |
3 | 11002211101200202102100212020 |
4 | 13013133303333031310121 |
5 | 13100321003122333423 |
6 | 150323415252205053 |
7 | 6410313564030564 |
oct | 707376377156431 |
9 | 132741622370766 |
10 | 31301520121113 |
11 | 9a7899a096790 |
12 | 361653b909789 |
13 | 146094a452228 |
14 | 7a30047954db |
15 | 3943573c04e3 |
hex | 1c77f3fcdd19 |
31301520121113 has 64 divisors (see below), whose sum is σ = 49583888640000. Its totient is φ = 17350508689920.
The previous prime is 31301520121043. The next prime is 31301520121163. The reversal of 31301520121113 is 31112102510313.
It is not a de Polignac number, because 31301520121113 - 29 = 31301520120601 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (31301520121163) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 172265853 + ... + 172447461.
It is an arithmetic number, because the mean of its divisors is an integer number (774748260000).
Almost surely, 231301520121113 is an apocalyptic number.
31301520121113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31301520121113 is a deficient number, since it is larger than the sum of its proper divisors (18282368518887).
31301520121113 is a wasteful number, since it uses less digits than its factorization.
31301520121113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191150.
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 31301520121113 its reverse (31112102510313), we get a palindrome (62413622631426).
The spelling of 31301520121113 in words is "thirty-one trillion, three hundred one billion, five hundred twenty million, one hundred twenty-one thousand, one hundred thirteen".
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