Base | Representation |
---|---|
bin | 11101001001110100… |
… | …101110110011101011 |
3 | 2222210120201222110112 |
4 | 131021310232303223 |
5 | 1003102123043201 |
6 | 22214111004535 |
7 | 2155503631556 |
oct | 351164566353 |
9 | 88716658415 |
10 | 31303331051 |
11 | 12303a06a33 |
12 | 609750974b |
13 | 2c4b3c82c5 |
14 | 172d59569d |
15 | c332760bb |
hex | 749d2eceb |
31303331051 has 2 divisors, whose sum is σ = 31303331052. Its totient is φ = 31303331050.
The previous prime is 31303330997. The next prime is 31303331057. The reversal of 31303331051 is 15013330313.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31303331051 is a prime.
It is not a weakly prime, because it can be changed into another prime (31303331057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15651665525 + 15651665526.
It is an arithmetic number, because the mean of its divisors is an integer number (15651665526).
Almost surely, 231303331051 is an apocalyptic number.
31303331051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31303331051 is an equidigital number, since it uses as much as digits as its factorization.
31303331051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1215, while the sum is 23.
Adding to 31303331051 its reverse (15013330313), we get a palindrome (46316661364).
The spelling of 31303331051 in words is "thirty-one billion, three hundred three million, three hundred thirty-one thousand, fifty-one".
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