Base | Representation |
---|---|
bin | 1110001111000100101001… |
… | …11111011100110101100011 |
3 | 11002211122200000012012110011 |
4 | 13013202110333130311203 |
5 | 13100342021124030103 |
6 | 150324543304145351 |
7 | 6410440533553642 |
oct | 707422477346543 |
9 | 132748600165404 |
10 | 31304221314403 |
11 | 9a7a055918234 |
12 | 3616b74468257 |
13 | 1460c8ac65b5b |
14 | 7a31bd419359 |
15 | 3944645ddd6d |
hex | 1c7894fdcd63 |
31304221314403 has 2 divisors, whose sum is σ = 31304221314404. Its totient is φ = 31304221314402.
The previous prime is 31304221314361. The next prime is 31304221314433. The reversal of 31304221314403 is 30441312240313.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31304221314403 is a prime.
It is a super-2 number, since 2×313042213144032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31304221314433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15652110657201 + 15652110657202.
It is an arithmetic number, because the mean of its divisors is an integer number (15652110657202).
Almost surely, 231304221314403 is an apocalyptic number.
31304221314403 is a deficient number, since it is larger than the sum of its proper divisors (1).
31304221314403 is an equidigital number, since it uses as much as digits as its factorization.
31304221314403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 31304221314403 its reverse (30441312240313), we get a palindrome (61745533554716).
The spelling of 31304221314403 in words is "thirty-one trillion, three hundred four billion, two hundred twenty-one million, three hundred fourteen thousand, four hundred three".
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