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3130431214214 = 21565215607107
BaseRepresentation
bin101101100011011100001…
…111011001001010000110
3102002021012010121110202202
4231203130033121022012
5402242110342323324
610354033353034502
7442111001166533
oct55433417311206
912067163543682
103130431214214
11aa76768a0497
124268470b5a32
13199276b54875
14ab72976dd8a
155666a3848ae
hex2d8dc3d9286

3130431214214 has 4 divisors (see below), whose sum is σ = 4695646821324. Its totient is φ = 1565215607106.

The previous prime is 3130431214213. The next prime is 3130431214219. The reversal of 3130431214214 is 4124121340313.

3130431214214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3130431214213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 782607803552 + ... + 782607803555.

It is an arithmetic number, because the mean of its divisors is an integer number (1173911705331).

Almost surely, 23130431214214 is an apocalyptic number.

3130431214214 is a deficient number, since it is larger than the sum of its proper divisors (1565215607110).

3130431214214 is a wasteful number, since it uses less digits than its factorization.

3130431214214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1565215607109.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 3130431214214 its reverse (4124121340313), we get a palindrome (7254552554527).

The spelling of 3130431214214 in words is "three trillion, one hundred thirty billion, four hundred thirty-one million, two hundred fourteen thousand, two hundred fourteen".

Divisors: 1 2 1565215607107 3130431214214