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313044124201649 is a prime number
BaseRepresentation
bin100011100101101100100001…
…1110100100111001010110001
31112001101201121020220210201022
41013023121003310213022301
5312012403331243423044
63025442252455345225
7122636456140000001
oct10713310364471261
91461351536823638
10313044124201649
11908222a4082a75
122b13a06b982215
1310589c1b6cc699
1457435b8a70001
15262cee1ad83ee
hex11cb643d272b1

313044124201649 has 2 divisors, whose sum is σ = 313044124201650. Its totient is φ = 313044124201648.

The previous prime is 313044124201643. The next prime is 313044124201709. The reversal of 313044124201649 is 946102421440313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 296416136227600 + 16627987974049 = 17216740^2 + 4077743^2 .

It is an emirp because it is prime and its reverse (946102421440313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313044124201649 - 216 = 313044124136113 is a prime.

It is a super-2 number, since 2×3130441242016492 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (313044124201643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156522062100824 + 156522062100825.

It is an arithmetic number, because the mean of its divisors is an integer number (156522062100825).

Almost surely, 2313044124201649 is an apocalyptic number.

It is an amenable number.

313044124201649 is a deficient number, since it is larger than the sum of its proper divisors (1).

313044124201649 is an equidigital number, since it uses as much as digits as its factorization.

313044124201649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 44.

The spelling of 313044124201649 in words is "three hundred thirteen trillion, forty-four billion, one hundred twenty-four million, two hundred one thousand, six hundred forty-nine".