Base | Representation |
---|---|
bin | 101101100011100010111… |
… | …010010010011010111111 |
3 | 102002021110221011222112200 |
4 | 231203202322102122333 |
5 | 402242323014401421 |
6 | 10354052431402543 |
7 | 442113530325606 |
oct | 55434272223277 |
9 | 12067427158480 |
10 | 3130543122111 |
11 | aa7723a85559 |
12 | 426878683453 |
13 | 1992940a7462 |
14 | ab73a580a3d |
15 | 566750dc726 |
hex | 2d8e2e926bf |
3130543122111 has 48 divisors (see below), whose sum is σ = 4609223324160. Its totient is φ = 2046928968000.
The previous prime is 3130543122097. The next prime is 3130543122131. The reversal of 3130543122111 is 1112213450313.
3130543122111 is a `hidden beast` number, since 3 + 1 + 3 + 0 + 5 + 431 + 221 + 1 + 1 = 666.
It is not a de Polignac number, because 3130543122111 - 230 = 3129469380287 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3130543122131) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 290640156 + ... + 290650926.
It is an arithmetic number, because the mean of its divisors is an integer number (96025485920).
Almost surely, 23130543122111 is an apocalyptic number.
3130543122111 is a deficient number, since it is larger than the sum of its proper divisors (1478680202049).
3130543122111 is a wasteful number, since it uses less digits than its factorization.
3130543122111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12308 (or 12305 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 3130543122111 its reverse (1112213450313), we get a palindrome (4242756572424).
The spelling of 3130543122111 in words is "three trillion, one hundred thirty billion, five hundred forty-three million, one hundred twenty-two thousand, one hundred eleven".
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