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313103520342521 is a prime number
BaseRepresentation
bin100011100110001000001100…
…0000110111010000111111001
31112001121101220200020101110122
41013030100120012322013321
5312014342002201430041
63025525434353023025
7122643661054603316
oct10714203006720771
91461541820211418
10313103520342521
11908455037067a7
122b149687554a75
13105926c600c57c
145746411253d0d
15262e81b309c4b
hex11cc4181ba1f9

313103520342521 has 2 divisors, whose sum is σ = 313103520342522. Its totient is φ = 313103520342520.

The previous prime is 313103520342479. The next prime is 313103520342551. The reversal of 313103520342521 is 125243025301313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 309616576605625 + 3486943736896 = 17595925^2 + 1867336^2 .

It is an emirp because it is prime and its reverse (125243025301313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313103520342521 - 238 = 312828642435577 is a prime.

It is not a weakly prime, because it can be changed into another prime (313103520342551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156551760171260 + 156551760171261.

It is an arithmetic number, because the mean of its divisors is an integer number (156551760171261).

Almost surely, 2313103520342521 is an apocalyptic number.

It is an amenable number.

313103520342521 is a deficient number, since it is larger than the sum of its proper divisors (1).

313103520342521 is an equidigital number, since it uses as much as digits as its factorization.

313103520342521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 313103520342521 its reverse (125243025301313), we get a palindrome (438346545643834).

The spelling of 313103520342521 in words is "three hundred thirteen trillion, one hundred three billion, five hundred twenty million, three hundred forty-two thousand, five hundred twenty-one".