Base | Representation |
---|---|
bin | 101101100100000001010… |
… | …111010010111111101000 |
3 | 102002022210112120110101201 |
4 | 231210001113102333220 |
5 | 402244344313334422 |
6 | 10354215242253544 |
7 | 442132303146322 |
oct | 55440127227750 |
9 | 12068715513351 |
10 | 3131054043112 |
11 | aa7966421016 |
12 | 42699b7b72b4 |
13 | 199345bb4388 |
14 | ab78837a612 |
15 | 566a4db1727 |
hex | 2d9015d2fe8 |
3131054043112 has 8 divisors (see below), whose sum is σ = 5870726330850. Its totient is φ = 1565527021552.
The previous prime is 3131054043053. The next prime is 3131054043119. The reversal of 3131054043112 is 2113404501313.
3131054043112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 1712920793796 + 1418133249316 = 1308786^2 + 1190854^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is not an unprimeable number, because it can be changed into a prime (3131054043119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 195690877687 + ... + 195690877702.
Almost surely, 23131054043112 is an apocalyptic number.
It is an amenable number.
3131054043112 is a deficient number, since it is larger than the sum of its proper divisors (2739672287738).
3131054043112 is a wasteful number, since it uses less digits than its factorization.
3131054043112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 391381755395 (or 391381755391 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 3131054043112 its reverse (2113404501313), we get a palindrome (5244458544425).
The spelling of 3131054043112 in words is "three trillion, one hundred thirty-one billion, fifty-four million, forty-three thousand, one hundred twelve".
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