31311123314113 has 2 divisors, whose sum is σ = 31311123314114. Its totient is φ = 31311123314112.

The previous prime is 31311123314099. The next prime is 31311123314117. The reversal of 31311123314113 is 31141332111313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28685793351744 + 2625329962369 = 5355912^2 + 1620287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31311123314113 is a prime.

It is a super-4 number, since 4×31311123314113⁴ (a number of 55 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (31311123314117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15655561657056 + 15655561657057.

It is an arithmetic number, because the mean of its divisors is an integer number (15655561657057).

Almost surely, 2^{31311123314113} is an apocalyptic number.

It is an amenable number.

31311123314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31311123314113 is an equidigital number, since it uses as much as digits as its factorization.

31311123314113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1944, while the sum is 28.

Adding to 31311123314113 its reverse (31141332111313), we get a palindrome (62452455425426).

The spelling of 31311123314113 in words is "thirty-one trillion, three hundred eleven billion, one hundred twenty-three million, three hundred fourteen thousand, one hundred thirteen".