Base | Representation |
---|---|
bin | 100011100110001101000100… |
… | …0110111011010101000011011 |
3 | 1112001122101222011101212012011 |
4 | 1013030122020313122220123 |
5 | 312020024434010310441 |
6 | 3025534330424130351 |
7 | 122644511601560146 |
oct | 10714321067325033 |
9 | 1461571864355164 |
10 | 313114002041371 |
11 | 908499a2318233 |
12 | 2b14b7119069b7 |
13 | 105936a6744a3b |
14 | 5746b2736705d |
15 | 262ec31618581 |
hex | 11cc688ddaa1b |
313114002041371 has 2 divisors, whose sum is σ = 313114002041372. Its totient is φ = 313114002041370.
The previous prime is 313114002041317. The next prime is 313114002041431. The reversal of 313114002041371 is 173140200411313.
Together with previous prime (313114002041317) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313114002041371 - 227 = 313113867823643 is a prime.
It is not a weakly prime, because it can be changed into another prime (313114002041471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156557001020685 + 156557001020686.
It is an arithmetic number, because the mean of its divisors is an integer number (156557001020686).
Almost surely, 2313114002041371 is an apocalyptic number.
313114002041371 is a deficient number, since it is larger than the sum of its proper divisors (1).
313114002041371 is an equidigital number, since it uses as much as digits as its factorization.
313114002041371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 313114002041371 its reverse (173140200411313), we get a palindrome (486254202452684).
The spelling of 313114002041371 in words is "three hundred thirteen trillion, one hundred fourteen billion, two million, forty-one thousand, three hundred seventy-one".
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