Base | Representation |
---|---|
bin | 101101100100000110101… |
… | …011001011110010010111 |
3 | 102002100000202020011211221 |
4 | 231210012223023302113 |
5 | 402300040121030201 |
6 | 10354232144111211 |
7 | 442134434401414 |
oct | 55440653136227 |
9 | 12070022204757 |
10 | 3131143142551 |
11 | aa7a01747816 |
12 | 426a05605507 |
13 | 19935b4ac438 |
14 | ab79613110b |
15 | 566acb114a1 |
hex | 2d906acbc97 |
3131143142551 has 8 divisors (see below), whose sum is σ = 3131975322000. Its totient is φ = 3130311084480.
The previous prime is 3131143142453. The next prime is 3131143142599. The reversal of 3131143142551 is 1552413411313.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3131143142551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3131143142651) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72712875 + ... + 72755923.
It is an arithmetic number, because the mean of its divisors is an integer number (391496915250).
Almost surely, 23131143142551 is an apocalyptic number.
3131143142551 is a deficient number, since it is larger than the sum of its proper divisors (832179449).
3131143142551 is a wasteful number, since it uses less digits than its factorization.
3131143142551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60689.
The product of its digits is 21600, while the sum is 34.
Adding to 3131143142551 its reverse (1552413411313), we get a palindrome (4683556553864).
The spelling of 3131143142551 in words is "three trillion, one hundred thirty-one billion, one hundred forty-three million, one hundred forty-two thousand, five hundred fifty-one".
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