Base | Representation |
---|---|
bin | 100011100110010000010101… |
… | …0000011100011101110010011 |
3 | 1112001200002000221210020010022 |
4 | 1013030200222003203232103 |
5 | 312020133302314322121 |
6 | 3025541445135054055 |
7 | 122645150211516221 |
oct | 10714405203435623 |
9 | 1461602027706108 |
10 | 313121001323411 |
11 | 90851964221446 |
12 | 2b150b4597132b |
13 | 10594250858c48 |
14 | 57471ccb77b11 |
15 | 262eee0d3eaab |
hex | 11cc82a0e3b93 |
313121001323411 has 2 divisors, whose sum is σ = 313121001323412. Its totient is φ = 313121001323410.
The previous prime is 313121001323399. The next prime is 313121001323453. The reversal of 313121001323411 is 114323100121313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313121001323411 - 210 = 313121001322387 is a prime.
It is a super-2 number, since 2×3131210013234112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (313121001322411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156560500661705 + 156560500661706.
It is an arithmetic number, because the mean of its divisors is an integer number (156560500661706).
Almost surely, 2313121001323411 is an apocalyptic number.
313121001323411 is a deficient number, since it is larger than the sum of its proper divisors (1).
313121001323411 is an equidigital number, since it uses as much as digits as its factorization.
313121001323411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 313121001323411 its reverse (114323100121313), we get a palindrome (427444101444724).
The spelling of 313121001323411 in words is "three hundred thirteen trillion, one hundred twenty-one billion, one million, three hundred twenty-three thousand, four hundred eleven".
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