31312140001 has 2 divisors, whose sum is σ = 31312140002. Its totient is φ = 31312140000.

The previous prime is 31312139959. The next prime is 31312140077. The reversal of 31312140001 is 10004121313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31179083776 + 133056225 = 176576^2 + 11535^2 .

It is a cyclic number.

It is not a de Polignac number, because 31312140001 - 2¹¹ = 31312137953 is a prime.

It is a super-2 number, since 2×31312140001² (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31312140091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656070000 + 15656070001.

It is an arithmetic number, because the mean of its divisors is an integer number (15656070001).

Almost surely, 2^31312140001 is an apocalyptic number.

It is an amenable number.

31312140001 is a deficient number, since it is larger than the sum of its proper divisors (1).

31312140001 is an equidigital number, since it uses as much as digits as its factorization.

31312140001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 31312140001 its reverse (10004121313), we get a palindrome (41316261314).

The spelling of 31312140001 in words is "thirty-one billion, three hundred twelve million, one hundred forty thousand, one".