Base | Representation |
---|---|
bin | 11101001010010110… |
… | …100111100001111111 |
3 | 2222211012110021202221 |
4 | 131022112213201333 |
5 | 1003111411323033 |
6 | 22215025230211 |
7 | 2155642300030 |
oct | 351226474177 |
9 | 88735407687 |
10 | 31312214143 |
11 | 12308a23a31 |
12 | 609a492367 |
13 | 2c501b8682 |
14 | 1730828a87 |
15 | c33e2d12d |
hex | 74a5a787f |
31312214143 has 4 divisors (see below), whose sum is σ = 35785387600. Its totient is φ = 26839040688.
The previous prime is 31312214119. The next prime is 31312214173. The reversal of 31312214143 is 34141221313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31312214143 - 233 = 22722279551 is a prime.
It is a super-4 number, since 4×313122141434 (a number of 43 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31312214173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2236586718 + ... + 2236586731.
It is an arithmetic number, because the mean of its divisors is an integer number (8946346900).
Almost surely, 231312214143 is an apocalyptic number.
31312214143 is a deficient number, since it is larger than the sum of its proper divisors (4473173457).
31312214143 is an equidigital number, since it uses as much as digits as its factorization.
31312214143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4473173456.
The product of its digits is 1728, while the sum is 25.
Adding to 31312214143 its reverse (34141221313), we get a palindrome (65453435456).
The spelling of 31312214143 in words is "thirty-one billion, three hundred twelve million, two hundred fourteen thousand, one hundred forty-three".
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