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31313122013321 is a prime number
BaseRepresentation
bin1110001111010101001111…
…00000111011000010001001
311002212111122022102112222122
413013222213200323002021
513101013233213411241
6150333014421101025
76411204232343321
oct707524740730211
9132774568375878
1031313122013321
119a82903055055
123618839257775
131461a78c887c5
147a37c5582281
153947d5c0304b
hex1c7aa783b089

31313122013321 has 2 divisors, whose sum is σ = 31313122013322. Its totient is φ = 31313122013320.

The previous prime is 31313122013309. The next prime is 31313122013339. The reversal of 31313122013321 is 12331022131313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20902406767225 + 10410715246096 = 4571915^2 + 3226564^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31313122013321 is a prime.

It is a super-3 number, since 3×313131220133213 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (31313122013021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656561006660 + 15656561006661.

It is an arithmetic number, because the mean of its divisors is an integer number (15656561006661).

Almost surely, 231313122013321 is an apocalyptic number.

It is an amenable number.

31313122013321 is a deficient number, since it is larger than the sum of its proper divisors (1).

31313122013321 is an equidigital number, since it uses as much as digits as its factorization.

31313122013321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 31313122013321 its reverse (12331022131313), we get a palindrome (43644144144634).

The spelling of 31313122013321 in words is "thirty-one trillion, three hundred thirteen billion, one hundred twenty-two million, thirteen thousand, three hundred twenty-one".