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31313200212641 is a prime number
BaseRepresentation
bin1110001111010101011000…
…01011001110101010100001
311002212111211202120111021202
413013222230023032222201
513101013413223301031
6150333030253130545
76411206202126554
oct707525413165241
9132774752514252
1031313200212641
119a82943206396
12361885b489a55
131461a8c2383a9
147a37d1ada69b
153947dc9ed2cb
hex1c7aac2ceaa1

31313200212641 has 2 divisors, whose sum is σ = 31313200212642. Its totient is φ = 31313200212640.

The previous prime is 31313200212631. The next prime is 31313200212649. The reversal of 31313200212641 is 14621200231313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31311533940241 + 1666272400 = 5595671^2 + 40820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31313200212641 is a prime.

It is not a weakly prime, because it can be changed into another prime (31313200212649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656600106320 + 15656600106321.

It is an arithmetic number, because the mean of its divisors is an integer number (15656600106321).

Almost surely, 231313200212641 is an apocalyptic number.

It is an amenable number.

31313200212641 is a deficient number, since it is larger than the sum of its proper divisors (1).

31313200212641 is an equidigital number, since it uses as much as digits as its factorization.

31313200212641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 31313200212641 its reverse (14621200231313), we get a palindrome (45934400443954).

The spelling of 31313200212641 in words is "thirty-one trillion, three hundred thirteen billion, two hundred million, two hundred twelve thousand, six hundred forty-one".