Base | Representation |
---|---|
bin | 100011100110110101101001… |
… | …0111001000000111101011011 |
3 | 1112001221201220012002111101102 |
4 | 1013031223102321000331123 |
5 | 312022441420142223121 |
6 | 3030042341404142015 |
7 | 122654015206326233 |
oct | 10715532271007533 |
9 | 1461851805074342 |
10 | 313201143320411 |
11 | 9088294a2a3a15 |
12 | 2b16459123790b |
13 | 1059b98321a048 |
14 | 574b032716cc3 |
15 | 2632131a0b90b |
hex | 11cdad2e40f5b |
313201143320411 has 2 divisors, whose sum is σ = 313201143320412. Its totient is φ = 313201143320410.
The previous prime is 313201143320323. The next prime is 313201143320437. The reversal of 313201143320411 is 114023341102313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313201143320411 - 210 = 313201143319387 is a prime.
It is not a weakly prime, because it can be changed into another prime (313201143320441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156600571660205 + 156600571660206.
It is an arithmetic number, because the mean of its divisors is an integer number (156600571660206).
Almost surely, 2313201143320411 is an apocalyptic number.
313201143320411 is a deficient number, since it is larger than the sum of its proper divisors (1).
313201143320411 is an equidigital number, since it uses as much as digits as its factorization.
313201143320411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 313201143320411 its reverse (114023341102313), we get a palindrome (427224484422724).
The spelling of 313201143320411 in words is "three hundred thirteen trillion, two hundred one billion, one hundred forty-three million, three hundred twenty thousand, four hundred eleven".
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