Base | Representation |
---|---|
bin | 1110001111100101111110… |
… | …11010110100001101110101 |
3 | 11002220100211220120000110201 |
4 | 13013302333122310031311 |
5 | 13101140141412002214 |
6 | 150341102521120501 |
7 | 6411643105435345 |
oct | 707627732641565 |
9 | 132810756500421 |
10 | 31322113000309 |
11 | 9a866a724a70a |
12 | 361a528329131 |
13 | 146287c901551 |
14 | 7a3dd96ccd25 |
15 | 394b601ee274 |
hex | 1c7cbf6b4375 |
31322113000309 has 4 divisors (see below), whose sum is σ = 31561213099680. Its totient is φ = 31083012900940.
The previous prime is 31322113000279. The next prime is 31322113000463. The reversal of 31322113000309 is 90300031122313.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31322113000309 - 217 = 31322112869237 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31322113000609) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119550049489 + ... + 119550049750.
It is an arithmetic number, because the mean of its divisors is an integer number (7890303274920).
Almost surely, 231322113000309 is an apocalyptic number.
It is an amenable number.
31322113000309 is a deficient number, since it is larger than the sum of its proper divisors (239100099371).
31322113000309 is a wasteful number, since it uses less digits than its factorization.
31322113000309 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239100099370.
The product of its (nonzero) digits is 2916, while the sum is 28.
The spelling of 31322113000309 in words is "thirty-one trillion, three hundred twenty-two billion, one hundred thirteen million, three hundred nine", and thus it is an aban number.
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