Base | Representation |
---|---|
bin | 1001000111011101001… |
… | …11111110011100110011 |
3 | 1002221112022101201011011 |
4 | 10203232213332130303 |
5 | 20113004210232011 |
6 | 355522335531351 |
7 | 31426256302546 |
oct | 4435647763463 |
9 | 1087468351134 |
10 | 313241102131 |
11 | 110932488311 |
12 | 5085b989b57 |
13 | 23700148c99 |
14 | 1123790c85d |
15 | 8234d88621 |
hex | 48ee9fe733 |
313241102131 has 2 divisors, whose sum is σ = 313241102132. Its totient is φ = 313241102130.
The previous prime is 313241102087. The next prime is 313241102159. The reversal of 313241102131 is 131201142313.
It is a strong prime.
It is an emirp because it is prime and its reverse (131201142313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 313241102131 - 211 = 313241100083 is a prime.
It is a super-2 number, since 2×3132411021312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (313241102171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156620551065 + 156620551066.
It is an arithmetic number, because the mean of its divisors is an integer number (156620551066).
Almost surely, 2313241102131 is an apocalyptic number.
313241102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
313241102131 is an equidigital number, since it uses as much as digits as its factorization.
313241102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 313241102131 its reverse (131201142313), we get a palindrome (444442244444).
The spelling of 313241102131 in words is "three hundred thirteen billion, two hundred forty-one million, one hundred two thousand, one hundred thirty-one".
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