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31325401631521 is a prime number
BaseRepresentation
bin1110001111101100000110…
…11011111100101100100001
311002220200100002200210101201
413013312003123330230201
513101213410304202041
6150342405120001201
76412120440360424
oct707660333745441
9132820302623351
1031325401631521
119a88034629a48
12361b0a5760201
131462c85032c8a
147a422c3899bb
15394ca3ca8631
hex1c7d836fcb21

31325401631521 has 2 divisors, whose sum is σ = 31325401631522. Its totient is φ = 31325401631520.

The previous prime is 31325401631509. The next prime is 31325401631527. The reversal of 31325401631521 is 12513610452313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25538317067025 + 5787084564496 = 5053545^2 + 2405636^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31325401631521 is a prime.

It is a super-3 number, since 3×313254016315213 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (31325401631527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15662700815760 + 15662700815761.

It is an arithmetic number, because the mean of its divisors is an integer number (15662700815761).

Almost surely, 231325401631521 is an apocalyptic number.

It is an amenable number.

31325401631521 is a deficient number, since it is larger than the sum of its proper divisors (1).

31325401631521 is an equidigital number, since it uses as much as digits as its factorization.

31325401631521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 31325401631521 in words is "thirty-one trillion, three hundred twenty-five billion, four hundred one million, six hundred thirty-one thousand, five hundred twenty-one".