Base | Representation |
---|---|
bin | 1001000111100100100… |
… | …00110100010011010001 |
3 | 1002221200120020202112011 |
4 | 10203302100310103101 |
5 | 20113120321440423 |
6 | 355532400102521 |
7 | 31430630152054 |
oct | 4436220642321 |
9 | 1087616222464 |
10 | 313302140113 |
11 | 110963988026 |
12 | 50878304a41 |
13 | 2370c99a531 |
14 | 11241a7aa9b |
15 | 823a3e3b0d |
hex | 48f24344d1 |
313302140113 has 2 divisors, whose sum is σ = 313302140114. Its totient is φ = 313302140112.
The previous prime is 313302140069. The next prime is 313302140141. The reversal of 313302140113 is 311041203313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 305728267329 + 7573872784 = 552927^2 + 87028^2 .
It is an emirp because it is prime and its reverse (311041203313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 313302140113 - 213 = 313302131921 is a prime.
It is not a weakly prime, because it can be changed into another prime (313302140183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156651070056 + 156651070057.
It is an arithmetic number, because the mean of its divisors is an integer number (156651070057).
Almost surely, 2313302140113 is an apocalyptic number.
It is an amenable number.
313302140113 is a deficient number, since it is larger than the sum of its proper divisors (1).
313302140113 is an equidigital number, since it uses as much as digits as its factorization.
313302140113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 313302140113 its reverse (311041203313), we get a palindrome (624343343426).
The spelling of 313302140113 in words is "three hundred thirteen billion, three hundred two million, one hundred forty thousand, one hundred thirteen".
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