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313312300314242 = 2156656150157121
BaseRepresentation
bin100011100111101001011010…
…0010111010010111010000010
31112002100100210220120211220212
41013033102310113102322002
5312031302042340023432
63030205403404234122
7122665031610226445
oct10717226427227202
91462310726524825
10313312300314242
1190916000546679
122b18203353b942
13105a92b9331488
14575257943365c
152634e8a4972b2
hex11cf4b45d2e82

313312300314242 has 4 divisors (see below), whose sum is σ = 469968450471366. Its totient is φ = 156656150157120.

The previous prime is 313312300314239. The next prime is 313312300314257. The reversal of 313312300314242 is 242413003213313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 309571321540321 + 3740978773921 = 17594639^2 + 1934161^2 .

It is a junction number, because it is equal to n+sod(n) for n = 313312300314199 and 313312300314208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78328075078559 + ... + 78328075078562.

Almost surely, 2313312300314242 is an apocalyptic number.

313312300314242 is a deficient number, since it is larger than the sum of its proper divisors (156656150157124).

313312300314242 is a wasteful number, since it uses less digits than its factorization.

313312300314242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156656150157123.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 313312300314242 its reverse (242413003213313), we get a palindrome (555725303527555).

The spelling of 313312300314242 in words is "three hundred thirteen trillion, three hundred twelve billion, three hundred million, three hundred fourteen thousand, two hundred forty-two".

Divisors: 1 2 156656150157121 313312300314242