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313322138317049 is a prime number
BaseRepresentation
bin100011100111101101111111…
…0110000010011000011111001
31112002101022012112112011200012
41013033123332300103003321
5312031432214402121144
63030214111522551305
7122665530446663411
oct10717337660230371
91462338175464605
10313322138317049
119091a199874804
122b183b1a208535
13105aa1c65ac104
145752c2dc67641
152635364005e9e
hex11cf6fec130f9

313322138317049 has 2 divisors, whose sum is σ = 313322138317050. Its totient is φ = 313322138317048.

The previous prime is 313322138317043. The next prime is 313322138317129. The reversal of 313322138317049 is 940713831223313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 297227944090000 + 16094194227049 = 17240300^2 + 4011757^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313322138317049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 313322138316988 and 313322138317006.

It is not a weakly prime, because it can be changed into another prime (313322138317043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156661069158524 + 156661069158525.

It is an arithmetic number, because the mean of its divisors is an integer number (156661069158525).

Almost surely, 2313322138317049 is an apocalyptic number.

It is an amenable number.

313322138317049 is a deficient number, since it is larger than the sum of its proper divisors (1).

313322138317049 is an equidigital number, since it uses as much as digits as its factorization.

313322138317049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1959552, while the sum is 50.

The spelling of 313322138317049 in words is "three hundred thirteen trillion, three hundred twenty-two billion, one hundred thirty-eight million, three hundred seventeen thousand, forty-nine".