Base | Representation |
---|---|
bin | 100011100111110010001011… |
… | …1011010101010010110000001 |
3 | 1112002102011110000120011210102 |
4 | 1013033210113122222112001 |
5 | 312032104134323311431 |
6 | 3030222201155212145 |
7 | 122666266536055655 |
oct | 10717442732522601 |
9 | 1462364400504712 |
10 | 313331142010241 |
11 | 90922a9a158763 |
12 | 2b1858115a7055 |
13 | 105aaccca53414 |
14 | 5753445960a65 |
15 | 26356de6b1dcb |
hex | 11cf9176aa581 |
313331142010241 has 2 divisors, whose sum is σ = 313331142010242. Its totient is φ = 313331142010240.
The previous prime is 313331142010223. The next prime is 313331142010247. The reversal of 313331142010241 is 142010241133313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 282808831920241 + 30522310090000 = 16816921^2 + 5524700^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313331142010241 is a prime.
It is not a weakly prime, because it can be changed into another prime (313331142010247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156665571005120 + 156665571005121.
It is an arithmetic number, because the mean of its divisors is an integer number (156665571005121).
Almost surely, 2313331142010241 is an apocalyptic number.
It is an amenable number.
313331142010241 is a deficient number, since it is larger than the sum of its proper divisors (1).
313331142010241 is an equidigital number, since it uses as much as digits as its factorization.
313331142010241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 313331142010241 its reverse (142010241133313), we get a palindrome (455341383143554).
The spelling of 313331142010241 in words is "three hundred thirteen trillion, three hundred thirty-one billion, one hundred forty-two million, ten thousand, two hundred forty-one".
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