Base | Representation |
---|---|
bin | 100011100111110010001101… |
… | …0111000101001100101011111 |
3 | 1112002102011121002001200101121 |
4 | 1013033210122320221211133 |
5 | 312032104244222444403 |
6 | 3030222211034351411 |
7 | 122666301143515315 |
oct | 10717443270514537 |
9 | 1462364532050347 |
10 | 313331200203103 |
11 | 90923019a94935 |
12 | 2b185828b8b567 |
13 | 105ab00bb19974 |
14 | 575344d58c0b5 |
15 | 26356e48593bd |
hex | 11cf91ae2995f |
313331200203103 has 4 divisors (see below), whose sum is σ = 313337211174720. Its totient is φ = 313325189231488.
The previous prime is 313331200203101. The next prime is 313331200203143. The reversal of 313331200203103 is 301302002133313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 313331200203103 - 21 = 313331200203101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (313331200203101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3005407618 + ... + 3005511871.
It is an arithmetic number, because the mean of its divisors is an integer number (78334302793680).
Almost surely, 2313331200203103 is an apocalyptic number.
313331200203103 is a deficient number, since it is larger than the sum of its proper divisors (6010971617).
313331200203103 is an equidigital number, since it uses as much as digits as its factorization.
313331200203103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6010971616.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 313331200203103 its reverse (301302002133313), we get a palindrome (614633202336416).
The spelling of 313331200203103 in words is "three hundred thirteen trillion, three hundred thirty-one billion, two hundred million, two hundred three thousand, one hundred three".
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