Base | Representation |
---|---|
bin | 100011100111110110011001… |
… | …1111111010011110111111011 |
3 | 1112002110000212002001112220222 |
4 | 1013033230303333103313323 |
5 | 312032231223044023141 |
6 | 3030230301134010255 |
7 | 123000040352634206 |
oct | 10717546377236773 |
9 | 1462400762045828 |
10 | 313340211314171 |
11 | 90926923584a68 |
12 | 2b18752294698b |
13 | 105abb1698a452 |
14 | 5753a6625693d |
15 | 2635a709cd14b |
hex | 11cfb33fd3dfb |
313340211314171 has 2 divisors, whose sum is σ = 313340211314172. Its totient is φ = 313340211314170.
The previous prime is 313340211314161. The next prime is 313340211314219. The reversal of 313340211314171 is 171413112043313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313340211314171 - 238 = 313065333407227 is a prime.
It is not a weakly prime, because it can be changed into another prime (313340211314111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156670105657085 + 156670105657086.
It is an arithmetic number, because the mean of its divisors is an integer number (156670105657086).
Almost surely, 2313340211314171 is an apocalyptic number.
313340211314171 is a deficient number, since it is larger than the sum of its proper divisors (1).
313340211314171 is an equidigital number, since it uses as much as digits as its factorization.
313340211314171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
Adding to 313340211314171 its reverse (171413112043313), we get a palindrome (484753323357484).
The spelling of 313340211314171 in words is "three hundred thirteen trillion, three hundred forty billion, two hundred eleven million, three hundred fourteen thousand, one hundred seventy-one".
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