Base | Representation |
---|---|
bin | 1001000111110000110… |
… | …10110110000011011001 |
3 | 1002221221202121112101112 |
4 | 10203320122312003121 |
5 | 20113323242311100 |
6 | 355550530030105 |
7 | 31433323134500 |
oct | 4437032660331 |
9 | 1087852545345 |
10 | 313405432025 |
11 | 110a07217844 |
12 | 508a6a18335 |
13 | 237281c44ca |
14 | 11251687837 |
15 | 82444e8b35 |
hex | 48f86b60d9 |
313405432025 has 72 divisors (see below), whose sum is σ = 460846039680. Its totient is φ = 210752976000.
The previous prime is 313405431949. The next prime is 313405432049. The reversal of 313405432025 is 520234504313.
It is not a de Polignac number, because 313405432025 - 214 = 313405415641 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 313405431982 and 313405432000.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 31145495 + ... + 31155555.
It is an arithmetic number, because the mean of its divisors is an integer number (6400639440).
Almost surely, 2313405432025 is an apocalyptic number.
313405432025 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
313405432025 is a deficient number, since it is larger than the sum of its proper divisors (147440607655).
313405432025 is a wasteful number, since it uses less digits than its factorization.
313405432025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10575 (or 10563 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 313405432025 its reverse (520234504313), we get a palindrome (833639936338).
The spelling of 313405432025 in words is "three hundred thirteen billion, four hundred five million, four hundred thirty-two thousand, twenty-five".
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