Search a number
-
+
313424555345351 = 430289728404759
BaseRepresentation
bin100011101000011101101011…
…1010010010000010111000111
31112002202002120011020021102122
41013100323113102100113013
5312040121442132022401
63030333130351200155
7123006114443236562
oct10720732722202707
91462662504207378
10313424555345351
1190959675592a5a
122b19b94151605b
13105b6a68a8a0c8
145757b87cdb4d9
152637d5a52c21b
hex11d0ed74905c7

313424555345351 has 4 divisors (see below), whose sum is σ = 313425284180400. Its totient is φ = 313423826510304.

The previous prime is 313424555345323. The next prime is 313424555345371. The reversal of 313424555345351 is 153543555424313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313424555345351 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313424555345293 and 313424555345302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313424555345371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363772091 + ... + 364632668.

It is an arithmetic number, because the mean of its divisors is an integer number (78356321045100).

Almost surely, 2313424555345351 is an apocalyptic number.

313424555345351 is a deficient number, since it is larger than the sum of its proper divisors (728835049).

313424555345351 is an equidigital number, since it uses as much as digits as its factorization.

313424555345351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 728835048.

The product of its digits is 32400000, while the sum is 53.

The spelling of 313424555345351 in words is "three hundred thirteen trillion, four hundred twenty-four billion, five hundred fifty-five million, three hundred forty-five thousand, three hundred fifty-one".

Divisors: 1 430289 728404759 313424555345351