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3134502055441 is a prime number
BaseRepresentation
bin101101100111001110111…
…000011010111000010001
3102002122200211121122010001
4231213032320122320101
5402323430011233231
610355545333210001
7442313611602361
oct55471670327021
912078624548101
103134502055441
11aa937576a789
124275a2490901
1319977534a963
14ab9d42849a1
155680794eb61
hex2d9cee1ae11

3134502055441 has 2 divisors, whose sum is σ = 3134502055442. Its totient is φ = 3134502055440.

The previous prime is 3134502055351. The next prime is 3134502055457. The reversal of 3134502055441 is 1445502054313.

3134502055441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2149801088400 + 984700967041 = 1466220^2 + 992321^2 .

It is a cyclic number.

It is not a de Polignac number, because 3134502055441 - 213 = 3134502047249 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3134502055441.

It is not a weakly prime, because it can be changed into another prime (3134502059441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567251027720 + 1567251027721.

It is an arithmetic number, because the mean of its divisors is an integer number (1567251027721).

Almost surely, 23134502055441 is an apocalyptic number.

It is an amenable number.

3134502055441 is a deficient number, since it is larger than the sum of its proper divisors (1).

3134502055441 is an equidigital number, since it uses as much as digits as its factorization.

3134502055441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 37.

The spelling of 3134502055441 in words is "three trillion, one hundred thirty-four billion, five hundred two million, fifty-five thousand, four hundred forty-one".