Base | Representation |
---|---|
bin | 1110010001110111000101… |
… | …01001010001011110110011 |
3 | 11010011210220220220112220111 |
4 | 13020323202221101132303 |
5 | 13103424211412412313 |
6 | 150440544513122151 |
7 | 6420401414104222 |
oct | 710734251213663 |
9 | 133153826815814 |
10 | 31400013404083 |
11 | a006741a73aa5 |
12 | 3631648b59357 |
13 | 146a015a5a21c |
14 | 7a7aa9684cb9 |
15 | 396bbe1d543d |
hex | 1c8ee2a517b3 |
31400013404083 has 2 divisors, whose sum is σ = 31400013404084. Its totient is φ = 31400013404082.
The previous prime is 31400013404057. The next prime is 31400013404171. The reversal of 31400013404083 is 38040431000413.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31400013404083 is a prime.
It is not a weakly prime, because it can be changed into another prime (31400013405083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700006702041 + 15700006702042.
It is an arithmetic number, because the mean of its divisors is an integer number (15700006702042).
Almost surely, 231400013404083 is an apocalyptic number.
31400013404083 is a deficient number, since it is larger than the sum of its proper divisors (1).
31400013404083 is an equidigital number, since it uses as much as digits as its factorization.
31400013404083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 31400013404083 its reverse (38040431000413), we get a palindrome (69440444404496).
The spelling of 31400013404083 in words is "thirty-one trillion, four hundred billion, thirteen million, four hundred four thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •