Base | Representation |
---|---|
bin | 11101001111100101… |
… | …111100011101101011 |
3 | 10000001022212021100220 |
4 | 131033211330131223 |
5 | 1003301412234443 |
6 | 22231445301123 |
7 | 2161060412613 |
oct | 351745743553 |
9 | 100038767326 |
10 | 31400118123 |
11 | 12353603550 |
12 | 6103a047a3 |
13 | 2c6548556a |
14 | 173c38ba43 |
15 | c3b9e3a83 |
hex | 74f97c76b |
31400118123 has 32 divisors (see below), whose sum is σ = 45885312000. Its totient is φ = 18942030240.
The previous prime is 31400118109. The next prime is 31400118133. The reversal of 31400118123 is 32181100413.
It is not a de Polignac number, because 31400118123 - 213 = 31400109931 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31400118093 and 31400118102.
It is not an unprimeable number, because it can be changed into a prime (31400118133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13998040 + ... + 14000282.
It is an arithmetic number, because the mean of its divisors is an integer number (1433916000).
Almost surely, 231400118123 is an apocalyptic number.
31400118123 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31400118123 is a deficient number, since it is larger than the sum of its proper divisors (14485193877).
31400118123 is a wasteful number, since it uses less digits than its factorization.
31400118123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4039.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 31400118123 its reverse (32181100413), we get a palindrome (63581218536).
The spelling of 31400118123 in words is "thirty-one billion, four hundred million, one hundred eighteen thousand, one hundred twenty-three".
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