Base | Representation |
---|---|
bin | 1110010001110111010011… |
… | …10010101001011100011001 |
3 | 11010011211020021111222222121 |
4 | 13020323221302221130121 |
5 | 13103424433111131131 |
6 | 150441004435021241 |
7 | 6420404401162030 |
oct | 710735162513431 |
9 | 133154207458877 |
10 | 31400133302041 |
11 | a0067a3716119 |
12 | 363168113a821 |
13 | 146a03484986a |
14 | 7a7abb575717 |
15 | 396bc99ba911 |
hex | 1c8ee9ca9719 |
31400133302041 has 24 divisors (see below), whose sum is σ = 36778396135680. Its totient is φ = 26260888401216.
The previous prime is 31400133301997. The next prime is 31400133302053. The reversal of 31400133302041 is 14020333100413.
It is not a de Polignac number, because 31400133302041 - 221 = 31400131204889 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31400133301997 and 31400133302015.
It is not an unprimeable number, because it can be changed into a prime (31400133305041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11061840 + ... + 13607518.
It is an arithmetic number, because the mean of its divisors is an integer number (1532433172320).
Almost surely, 231400133302041 is an apocalyptic number.
It is an amenable number.
31400133302041 is a deficient number, since it is larger than the sum of its proper divisors (5378262833639).
31400133302041 is an equidigital number, since it uses as much as digits as its factorization.
31400133302041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2546725 (or 2546682 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 31400133302041 its reverse (14020333100413), we get a palindrome (45420466402454).
The spelling of 31400133302041 in words is "thirty-one trillion, four hundred billion, one hundred thirty-three million, three hundred two thousand, forty-one".
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