Base | Representation |
---|---|
bin | 1001001000110111111… |
… | …00011010011000011111 |
3 | 1010000111022002120121001 |
4 | 10210123330122120133 |
5 | 20121033331343033 |
6 | 400130020251131 |
7 | 31454151103135 |
oct | 4443374323037 |
9 | 1100438076531 |
10 | 314001434143 |
11 | 111192694a81 |
12 | 50a32540aa7 |
13 | 237c1820497 |
14 | 112aa8ad755 |
15 | 827b9c6e7d |
hex | 491bf1a61f |
314001434143 has 4 divisors (see below), whose sum is σ = 314137426680. Its totient is φ = 313865441608.
The previous prime is 314001434077. The next prime is 314001434171. The reversal of 314001434143 is 341434100413.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 314001434143 - 225 = 313967879711 is a prime.
It is a super-2 number, since 2×3140014341432 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (314001431143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67992805 + ... + 67997422.
It is an arithmetic number, because the mean of its divisors is an integer number (78534356670).
Almost surely, 2314001434143 is an apocalyptic number.
314001434143 is a deficient number, since it is larger than the sum of its proper divisors (135992537).
314001434143 is a wasteful number, since it uses less digits than its factorization.
314001434143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 135992536.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 314001434143 its reverse (341434100413), we get a palindrome (655435534556).
The spelling of 314001434143 in words is "three hundred fourteen billion, one million, four hundred thirty-four thousand, one hundred forty-three".
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