Base | Representation |
---|---|
bin | 100011101100101011010100… |
… | …1100111010100101011101001 |
3 | 1112011210110012110011100121212 |
4 | 1013121112221213110223221 |
5 | 312124113343040413342 |
6 | 3031455133351442505 |
7 | 123066004112115431 |
oct | 10731265147245351 |
9 | 1464713173140555 |
10 | 314003609701097 |
11 | 91062201689a58 |
12 | 2b274005686435 |
13 | 1062954b154674 |
14 | 5777bda45b2c1 |
15 | 2647e4b5d8182 |
hex | 11d95a99d4ae9 |
314003609701097 has 2 divisors, whose sum is σ = 314003609701098. Its totient is φ = 314003609701096.
The previous prime is 314003609701091. The next prime is 314003609701123. The reversal of 314003609701097 is 790107906300413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 201554212726441 + 112449396974656 = 14196979^2 + 10604216^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-314003609701097 is a prime.
It is not a weakly prime, because it can be changed into another prime (314003609701091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157001804850548 + 157001804850549.
It is an arithmetic number, because the mean of its divisors is an integer number (157001804850549).
Almost surely, 2314003609701097 is an apocalyptic number.
It is an amenable number.
314003609701097 is a deficient number, since it is larger than the sum of its proper divisors (1).
314003609701097 is an equidigital number, since it uses as much as digits as its factorization.
314003609701097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 857304, while the sum is 50.
The spelling of 314003609701097 in words is "three hundred fourteen trillion, three billion, six hundred nine million, seven hundred one thousand, ninety-seven".
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