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3140041030331 is a prime number
BaseRepresentation
bin101101101100011001000…
…001111011101010111011
3102010011222212011201020012
4231230121001323222323
5402421301000432311
610402303120452135
7442601100242252
oct55543101735273
912104885151205
103140041030331
111000758334587
1242868947a04b
1319a148a596aa
14abd9bb65799
1556a2dd6c78b
hex2db1907babb

3140041030331 has 2 divisors, whose sum is σ = 3140041030332. Its totient is φ = 3140041030330.

The previous prime is 3140041030307. The next prime is 3140041030339. The reversal of 3140041030331 is 1330301400413.

3140041030331 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3140041030331 - 226 = 3139973921467 is a prime.

It is a super-2 number, since 2×31400410303312 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 3140041030297 and 3140041030306.

It is not a weakly prime, because it can be changed into another prime (3140041030339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570020515165 + 1570020515166.

It is an arithmetic number, because the mean of its divisors is an integer number (1570020515166).

Almost surely, 23140041030331 is an apocalyptic number.

3140041030331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140041030331 is an equidigital number, since it uses as much as digits as its factorization.

3140041030331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 3140041030331 its reverse (1330301400413), we get a palindrome (4470342430744).

The spelling of 3140041030331 in words is "three trillion, one hundred forty billion, forty-one million, thirty thousand, three hundred thirty-one".