31400441220013 has 4 divisors (see below), whose sum is σ = 31400521369180. Its totient is φ = 31400361070848.

The previous prime is 31400441219933. The next prime is 31400441220023. The reversal of 31400441220013 is 31002214400413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 16146276807049 + 15254164412964 = 4018243^2 + 3905658^2 .

It is a cyclic number.

It is not a de Polignac number, because 31400441220013 - 2¹⁷ = 31400441088941 is a prime.

It is a super-2 number, since 2×31400441220013² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 31400441220013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31400441220023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39484020 + ... + 40271437.

It is an arithmetic number, because the mean of its divisors is an integer number (7850130342295).

Almost surely, 2^{31400441220013} is an apocalyptic number.

It is an amenable number.

31400441220013 is a deficient number, since it is larger than the sum of its proper divisors (80149167).

31400441220013 is an equidigital number, since it uses as much as digits as its factorization.

31400441220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80149166.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 31400441220013 its reverse (31002214400413), we get a palindrome (62402655620426).

The spelling of 31400441220013 in words is "thirty-one trillion, four hundred billion, four hundred forty-one million, two hundred twenty thousand, thirteen".